Let's use this moster to do some multiplying! For each question please show your either the multiplication fact, the repeated addition, or the skip counting.
1. If there are 5 of these monsters, how many arms do they have in all?
2. If there are 8 of these monsters, how many antennae do they have in all?
3. If there are 6 of these monsters, how many eyes do they have in all?
4. If there are 3 of these monsters, how many teeth do they have in all?
1. Monster has 2 arms so 2+2+2+2+2=10 arms
ReplyDelete2. 2 antennae so 2+2+2+2+2+2+2+2=16 antennae
3.Monster has 1 eye so 1+1+1+1+1+1=6 eyes
4.Monster has 2 teeth so 2+2+2=6 teeth
Sincerely,
LMW
P.S. It's good practice!!!
1.2x5=10
ReplyDelete2.2x8=16
3.2x6=12
4.2x3=6
HAM
Oops!!! Sorry 4 arms so 2+2+2+2=8 arms
ReplyDeleteLmw ( at home)
1.4,8,12,16,20 they would have 20 arms.
ReplyDelete2.2,4,6,8,10,12,14 they would have 14 antennaes.
3.1,2,3,4,5,6they would have 6 eyes.
4.2,4,6 they would have 6 teeth.
gz
4x5=20 2x8=16 1x6=6 2x3=6
ReplyDelete20 16 6 6
_-NL_
If there are 5 of these monsters, they would have 20 arms in all. If there are 8 of these monsters, they would have 16 antennae in all.If there are 6 of these monsters, they would have 6 eyes in all. If there are 3 of these monsters, they would have 6 teeth in all.
ReplyDeleteKW
1.2x10=20 20 arms
ReplyDelete2.2x8=16 16 antennaes
3.3x2=6 6 eyes
4.2x3=6 6 teeth
-ljf
1. 4+ 4+ 4+ 4+ 4+ = 20
ReplyDelete2. 2+ 2+ 2+ 2+ 2+ 2+ 2+ 2+ = 16
3. 1+ 1+ 1+ 1+ 1+ 1+ = 6
4. 3+ 3+ 3+ = 9
-ClB